...程序功能:输入一个正整数n,计算1-1/2+2/3-3/5+...的前n项和_百度...
发布网友
发布时间：2024-10-24 04:25
共2个回答
热心网友
时间：2024-11-03 03:08
c:
#include<stdio.h>int main() {
int flag=1,i,n,temp;
double fz=1.0,fm=1.0,sum;
printf("请输入一个正整数：");
scanf("%d",&n);
// *********************************************************************
for(int i=1;i<=n;i++){
sum+=(flag*fz/fm);
flag=-flag;
fm=fz+fm;
fz=fm-fz;
}
// *********************************************************************
printf("1-1/2+2/3-3/5+...的前%d项之和等于%0.2f\n", n,sum);
}
热心网友
时间：2024-11-03 03:08
#include<stdio.h>
#include<math.h>
int main(){
double fm=2.0,fz = 1.0,sum = 0,num =1 ,t = 0;
int i,n;
printf("输入一个正整数\n");
scanf("%d",&n);
for(i = 1;i<=n;i++){
if(i>1){
num = (fz/(fm));
t = fz;
fz = fm;
fm = fm+t;
if(i%2 == 0)
num = -num;
}
sum = sum + num;
}
printf("sum = %lf",sum);
return 0;
}
不谢
