初中分式运算,要过程,谢谢
发布网友
发布时间：2024-10-24 09:54
共1个回答
热心网友
时间：2024-11-14 14:04
解：原式=[(x-1)(x+2)-(x+1)(x-1)]/(x+1)(x+2)x(x+2)^2/(x+3)
=(-x-3)/(x+1)(x+2)x(x+2)^2/(x+3)
=-(x+2)/(x+1)
答：答案是-（x+2）/(x+1)。
热心网友
时间：2024-11-14 14:04
解：原式=[(x-1)(x+2)-(x+1)(x-1)]/(x+1)(x+2)x(x+2)^2/(x+3)
=(-x-3)/(x+1)(x+2)x(x+2)^2/(x+3)
=-(x+2)/(x+1)
答：答案是-（x+2）/(x+1)。
热心网友
时间：2024-11-14 14:04
解：原式=[(x-1)(x+2)-(x+1)(x-1)]/(x+1)(x+2)x(x+2)^2/(x+3)
=(-x-3)/(x+1)(x+2)x(x+2)^2/(x+3)
=-(x+2)/(x+1)
答：答案是-（x+2）/(x+1)。
