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2012~2020北京市高考数学分类汇编01集合

2022-03-11 来源:易榕旅网
2012~2020北京市高考数学分类汇编01集合

(2012文/理)(1)已知集合A{xR|3x20},B{xR|(x1)(x3)0},则AB

(A)(,1)

2(B)(1,)

32(C)(,3)

3(D)(3,)

(2013文/理)(1)已知集合A{1,0,1},B{x|1≤x1},则A(A){0} (C){0,1}

(B){1,0} (D){1,0,1}

B

(2014文)(1)若集合A{0,1,2,4},B{1,2,3},则A(A){0,1,2,3,4} (C){1,2}

(B){0,4} (D){3}

B

(2014理)(1)已知集合A{xx22x0},B{0,1,2},则A(A){0} (C){0,2}

(B){0,1} (D){0,1,2}

B

(2015文)(1)若集合A{x|5x2},B{x|3x3},则A(A){x|3x2} (C){x|3x3}

(B){x|5x2} (D){x|5x3}

B

(2016理)(1)已知集合A{x||x|2},B{1,0,1,2,3},则A(A){0,1} (C){1,0,1}

(B){0,1,2} (D){1,0,1,2}

B

(2016文)(1)已知集合A{x|2x4},B{x|x3或x5},则A(A){x|2x5} (C){x|2x3}

(B){x|x4或x5} (D){x|x2或x5}

B

(2017理)(1)若集合A{x|2x1},B{x|x1或x3},则AB

(A){x|2x1} (C){x|1x1}

(B){x|2x3} (D){x|1x3}

U(2017文)(1)已知全集UR,集合A{x|x2或x2},则

(A)(2,2) (C)[2,2]

A

(B)(,2)(2,) (D)(,2][2,)

(2018理)(1)已知集合A{x|x|2},B{2,0,1,2},则AB

(A){0,1}

(B){1,0,1}

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(C){2,0,1,2} (D){1,0,1,2}

(2018理)(8)设集合A(x,y)xy≥1,axy4,xay≤2,则

(A)对任意实数a,(2,1)A (C)当且仅当a0时,(2,1)A

(B)对任意实数a,(2,1)A (D)当且仅当a≤3时,(2,1)A 2(2018文)(8)设集合A(x,y)xy≥1,axy4,xay≤2,则

(A)对任意实数a,(2,1)A (C)当且仅当a0时,(2,1)A

(B)对任意实数a,(2,1)A 3(D)当且仅当a≤时,(2,1)A

2(2018文)(1)已知集合A{x|x|2},B{2,0,1,2},则AB

(A){0,1} (C){2,0,1,2}

(B){1,0,1} (D){1,0,1,2}

(2019文)(1)已知集合A{x|1x2},B{x|x1},则AB

(A)(1,1) (C)(1,)

(B)(1,2) (D)(1,)

(2020)1.已知集合A{1,0,1,2},B{x|0x3},则AA. {1,0,1} 【答案】D

B. {0,1}

C. {1,1,2}

B( ).

D. {1,2}

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