...已知抛物线y2=4x的焦点为F,过F的直线交抛物线于M、N两点,其准线l...

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热心网友 时间:2024-11-20 14:08

(1)证明:抛物线焦点坐标为F(1,0),准线方程为x=-1….(2分)
设直线MN的方程为x=my+1,M、N的坐标分别为(y124,y1),(y224,y2)
由x=my+1y2=4x?y2?4my?4=0,∴y1+y2=4m,y1y2=-4…..(4分)
设KM和KN的斜率分别为k1,k2,显然只需证k1+k2=0即可.
∵K(-1,0)
∴k1+k2=y1y214+1+y2y224+1=4(y1+y2)(y1y2+4)(y21+4)(y21+4)=0…(6分)
(2)解:设M、N的坐标分别为(y124,y1),(y224,y2),
由M,O,P三点共线可得P点的坐标为(?1,?4y1),
同理可由N,O,Q三点共线可求出Q点坐标为(?1,?4y本回答由提问者推荐已赞过已踩过你对这个回答的评价是?评论收起 ._1uevpeq{zoom:1;background-color:#fff;border:0;margin-bottom:10px;padding:30px 0 20px 42px;position:relative}._1uevpeq.ec-1841{padding:20px 0}._1uevpeq.ec-2246{padding:20px 0 10px}.ec-1841 .y7we4hu{font-size:16px;margin-bottom:-5px}.y7we4hu{color:#7a8f9a;height:25px;line-height:25px;overflow:hidden;position:relative}.y7we4hu h2{margin:0;padding:0}.y7we4hu:after{clear:both;content:" ";display:block;height:0;visibility:hidden}a.tycfu7u{color:#666;float:right;font-size:12px;margin-left:8px;text-decoration:none}.hhhv6ex{color:#666;font-size:13px;line-height:normal;line-height:20px;margin-top:10px}.vnsdjzp{margin-top:15px;position:relative}.vnsdjzp h3{font-weight:400;padding:0}.vnsdjzp a{text-decoration:none}.vnsdjzp em{color:#d81419;font-style:normal}.ec-2246 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